a^2+9a-90=0

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Solution for a^2+9a-90=0 equation: 



a^2+9a-90=0

a = 1; b = 9; c = -90;
Δ = b2-4ac
Δ = 92-4·1·(-90)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-21}{2*1}=\frac{-30}{2}
=-15
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+21}{2*1}=\frac{12}{2}
=6
$

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